Json 使用 jq 获取特定键的所有父键

我想要做的是在我的json上‘遍历’，并 for each 名为‘base’的键添加一个键，它是这个键的完整‘路径’.

This is my JSON:个

{
  "entity": {
    "product": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": ["product", "products", "pdt", "pdts"]
      }
    },
    "rabbit": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": ["rabbit", "rabbits"]
      }
    }
  }
}

And I want a result like this :个

{
  "entity": {
    "product": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": ["product", "products", "pdt", "pdts"],
        "path": "entity.product.title"
      }
    },
    "rabbit": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": ["rabbit", "rabbits"]
        "path": "entity.rabbit.title"
      }
    }
  }
}

实际上，我做到了这一点，但我只得到了一个子密钥:

walk(if type == "object" and .base then  keys[] as $k | .base |= {path: $k} else . end)

结果:

{
  "entity": {
    "product": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": {
          "path": "base"
        }
      }
    },
    "rabbit": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": {
          "path": "base"
        }
      }
    }
  }
}

我还try 了这个:

walk(if type == "object" and .base then  paths(..) as $v | .base |= {path: $v} else . end)

结果:

{
  "entity": {
    "product": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": {
          "path": [
            "base",
            3
          ]
        }
      }
    },
    "rabbit": {
      "att": {
        "number_of_values": "Number of values"
      },
      "title": {
        "base": {
          "path": [
            "base",
            1
          ]
        }
      }
    }
  }
}

我们非常感谢您的建议和专业知识！