我有一个功能,可以从url中删除youtube id.然后我希望每页使用这个函数10次(在wordpress循环中).
当我在函数脚本标记中向其提供url时,该函数非常有效,但当我在循环中启动一组新的脚本标记时,它就不起作用了.
我需要知道如何使用我的函数而不首先声明它.
这是我在标题中的代码:
<script type="text/javascript">
$(document).ready(function() {
var getList = function(url, gkey){
var returned = null;
if (url.indexOf("?") != -1){
var list = url.split("?")[1].split("&"),
gets = [];
for (var ind in list){
var kv = list[ind].split("=");
if (kv.length>0)
gets[kv[0]] = kv[1];
}
returned = gets;
if (typeof gkey != "undefined")
if (typeof gets[gkey] != "undefined")
returned = gets[gkey];
}
return returned;
};
// THIS WORKS
alert(getList('http://www.youtube.com/watch?v=dm4J5dAUnR4', "v"));
});
But when I try use this somewhere else on the page, it doesnt work.
<script type="text/javascript">
$(document).ready(function() {
alert(getList('http://www.youtube.com/watch?v=dm4J5dAUnR4', "v"));
};
</script>
Firebug gives me getList is not defined which makes sense, because its not. Am I able to 'globally' declare this function?