将变量传递给jQuery AJAX成功回调中的函数

I am trying to preload some images with a jQuery AJAX call, but am having real problems passing a (url) string into a function within the success function of the AJAX call (if that makes sense).

Here is my code as is stands:

//preloader for images on gallery pages
window.onload = function() {
    setTimeout(function() {     
        var urls = ["./img/party/"]; //just one to get started

        for ( var i = 0; i < urls.length; i++ ) {
            $.ajax({
                url: urls[i],
                success: function(data,url) {
                    $(data).find("a:contains(.jpg)").each(function(url) {                               
                        new Image().src = url + $(this).attr("href");
                    });
                }
            });
        };  
    }, 1000);
};

可以看到我(失败)try 将url传递到.each()调用中，结果是url接受递增整数的值.不知道为什么或者这些与什么有关，也许是jpg文件的数量？

...anyway, it should of course take the single value in my original urls array.

谢谢你的帮助——我似乎总是对这些回电感到有些纠结.

PROGESS?

So, I mucked around a bit, taking heed of comments from @ron tornambe and @PiSquared and am currently here:

//preloader for images on gallery pages
window.onload = function() {
    var urls = ["./img/party/","./img/wedding/","./img/wedding/tree/"];

    setTimeout(function() {
        for ( var i = 0; i < urls.length; i++ ) {
            $.ajax({
                url: urls[i],
                success: function(data) {
                    image_link(data,i);
                    function image_link(data, i) {
                        $(data).find("a:contains(.jpg)").each(function(){ 
                            console.log(i);
                            new Image().src = urls[i] + $(this).attr("href");
                        });
                    }
                }
            });
        };  
    }, 1000);       
};

我试着把image_link(data, i)放在这里、那里和任何地方(在每个嵌套函数中等等)，但我得到了相同的结果:i的值只记录为3.我怀疑这是因为对i的所有引用都指向同一个对象，当异步任务实际达到image_link(data, i)时，for...循环就结束了(因此值为3).不用说，这将urls[i]定义为"未定义".

Any (more) tips how I can get round this?