Javascript Promise.all立即跳到那时，而不是调用所有Promise

我对promise 很陌生，并试图让Promises.All在这种情况下发挥作用. 然而，当我try 通过调用changeFile函数来运行代码时，它会立即到达Promises.all then方法中的console.log行. 我做错了什么？

let doc1Text = "";
let doc2Text = "";

const processDoc = async (fileInput) => {
    var input = document.getElementById(fileInput);
    
    await fetch(urls.GetContractLanguageText, {
      method: 'POST',
      body: input.files[0]
    })
    .then(j => j.json())
    .then(x => {                    
        return x.ConvertedText;
    });
}

const processDoc1 = async () => {
    $(selectors.fileProgress1).val(0);
    doc1Text = await processDoc(selectors.baseFile);
    $(selectors.fileProgress1).val(100);
};

const processDoc2 = async () =>  {
    $(selectors.fileProgress2).val(0);
    doc1Text = await processDoc(selectors.newFile);
    $(selectors.fileProgress2).val(100);
};

const processFiles = async () => {
    $(selectors.aiComparison).removeClass(selectors.hide);
    await Promise.all([processDoc1, processDoc2])
        .then(() => {
          console.log(doc1Text, doc2Text);
        });
}