Javascript 编剧如何获得一个div内的所有链接，然后判断每个链接是否都会得到200

在更高的层面上，我想

1. 转到某个页面，然后使用某个定位器(div等)，在这个定位器中拉出a个标签的所有href个链接.
2. 然后我想要单独转到每个链接，看看它是否有效，或者是一个断开的链接，这意味着判断状态代码是否为200.
3. 这里需要注意的是，第二个点应该并行运行，否则以串行方式判断每个链接将非常慢.

这是我目前拥有的代码(我已经删除了一些敏感信息，如URL等).

test.describe(`@Header Tests`, () => {
  test.beforeEach(async ({ page, context }) => {
    await page.goto(".....some url.....");
  });
  test(`@smoke Validate all header links give a status of 200`, async ({
    page,
  }) => {
    const elements = page.locator("section#mega-nav a");
    const links = await elements.evaluateAll<string[], HTMLAnchorElement>(
      (itemTexts) =>
        itemTexts
          .map((item) => item.href)
          .filter((href) => href !== "" && !href.includes("javascript:"))
    );

    // visit each link
    for (const link of links) {
      test(`Check status code for ${link}`, async () => {
        // Visit the link
        const response = await page.goto(link, {
          waitUntil: "domcontentloaded",
        });

        // Check if the response status code is 200
        expect(response?.status()).toBe(200);
      });
    }
  });
});

但当我运行此命令时，我收到以下错误

    Error: Playwright Test did not expect test() to be called here.
    Most common reasons include:
    - You are calling test() in a configuration file.
    - You are calling test() in a file that is imported by the configuration file.
    - You have two different versions of @playwright/test. This usually happens
      when one of the dependencies in your package.json depends on @playwright/test.

在剧作家身上能做到这一点吗？也就是说，首先获取页面div等上的所有链接，然后并行地转到每个链接以判断它们的状态代码？