Javascript 如何在JS中过滤具有相同名称和状态的对象数组

嗨，我只关注了code

    [
      {service: { name: "Home" },status: "Generated", feeCharged:{id:1,fee:2},
      {service: { name: " Photography" },status: "requested",feeCharged:{id:2,fee:24}},
      {service: { name: "Electrical" },status: "requested",feeCharged:{id:6,fee:42}},
      {service: { name: "Electrical" },status: "Completed",feeCharged:{id:66,fee:23} },
      {service: { name: " Photography" },status: "Completed",feeCharged:{id:78,fee:11}},
      {service: { name: "Home" },status: "Generated",feeCharged:{id:45,fee:234}},
      {service: { name: "Electrical" }, status: "requested",feeCharged:{id:77,fee:3} },
      {service: { name: "Electrical" }, status: "requested",feeCharged:{id:4,fee:33} }
    ]

现在，我正在try 按service.name和status再加上count来筛选新数组中的数据.

最终结果应该是:

    [
      { name: "Home", status: "Generated", count: 2 },
      { name: "Photography", status: "requested", count: 1 },
      { name: "Photography", status: "Completed", count: 1 },
      { name: "Electrical", status: "requested", count: 3 },
      { name: "Electrical", status: "Completed", count: 1 }
    ]

所以，正如你在我的最终结果中看到的，如果有相同的service.name和status，我将它们合并到一个对象中，并设置计数.

对于过滤，我try 了这个，但它并不像我预期的那样工作:

   let answer = [];

    data.forEach((x) => {
    if (!answer.some((y) => y.name === x.service.name)) {
      let newAnswer = {};
      newAnswer.name = x.service.name;
      newAnswer.value = 1;
      answer.push(newAnswer);
    } else {
      let existAnswer = answer.find((y) => y.name === x.service.name);
      existAnswer.value++;
    }
    });

请帮助我实现这个结果，谢谢.