我们在Safari浏览器中使用我们正在使用的regex时遇到了一些问题.下面是正则表达式:
/(?<=type: ).*./g个
Safari无法处理此问题，因此我们将其更改为:
/(?:)(type: ).*./g个
问题是，现在对于Chrome，它不能返回正确的值.有没有办法让一个正则表达式同时适用于Chrome和Safari，并获得相同的响应？因此，我们希望得到的回应是:
BUSINESS
ACC
false
Code Example个
const query = "{\n testObject(testInput : {\n id: \"id-13\",\n life: ACC,\n type: BUSINESS,\n promo: [],\n isvalid: false\n })}\n }"
const pattern = /\(([^)]+)\)/g;
const result = query.match(pattern) ? query.match(pattern).map((v) => v.trim().replace(/^\(|\)$/g, ''))[0] : null;
/* DOES NOT WORK IN SAFARI */
const queryTypePattern = /(?<=type: ).*./g;
const queryLifePattern = /(?<=life: ).*./g;
const queryIsValidPattern = /(?<=isvalid: ).*./g;
const queryType = result.match(queryTypePattern) ? result.match(queryTypePattern).map((v) => v.trim().replace(',', ''))[0] : null;
const queryLife = result.match(queryLifePattern) ? result.match(queryLifePattern).map((v) => v.trim().replace(',', ''))[0] : null;
const queryIsValid = result.match(queryIsValidPattern) ? result.match(queryIsValidPattern).map((v) => v.trim().replace(',', ''))[0] : null;
console.log('#### RETURNS THE CORRECT OUTPUT IN CHROME: ');
console.log(queryType);
console.log(queryLife);
console.log(queryIsValid);
/* WORKS IN SAFARI */
const queryTypePattern2 = /(?:type: ).*./g;
const queryLifePattern2 = /(?:life: ).*./g;
const queryIsValidPattern2 = /(?:isvalid: ).*./g;
const queryType2 = result.match(queryTypePattern2) ? result.match(queryTypePattern2).map((v) => v.trim().replace(',', ''))[0] : null;
const queryLife2 = result.match(queryLifePattern2) ? result.match(queryLifePattern2).map((v) => v.trim().replace(',', ''))[0] : null;
const queryIsValid2 = result.match(queryIsValidPattern2) ? result.match(queryIsValidPattern2).map((v) => v.trim().replace(',', ''))[0] : null;
console.log('#### RETURNS THE INCORRECT OUTPUT IN CHROME: ');
console.log(queryType2);
console.log(queryLife2);
console.log(queryIsValid2);