Javascript Typescript嵌套函数包装返回类型问题

我正在调用下面的函数，返回Promise<boolean>

const fnc = (i:number) : Promise<boolean>  => Promise.resolve(true)

// Promise<boolean>
const res1 = errorHandler(errorPredicates.sdkError1, fnc, null, 4);

然而，当我用另一个错误处理程序嵌套它时，返回的对象变为Promise<any>

// Promise<any>
const res2 = errorHandler(errorPredicates.sdkError1, errorHandler, null, errorPredicates.sdkError2, fnc, null, 4);

下面是复制问题的typescript代码示例.我不确定这里出了什么问题，也不确定这是否是typescript的限制.我如何解决这个打字问题？

type PromiseFn = (...args: any[]) => Promise<any>;
type UnwrappedReturnType<T extends PromiseFn> = T extends (...args: any) => Promise<infer R> ? R : any

type ThrottlerPredicate = (err: any) => boolean;

type ThrottlerPredicates = {
    sdkError1: ThrottlerPredicate
    sdkError2: ThrottlerPredicate
}

const errorPredicates: ThrottlerPredicates = {
    sdkError1: (err) => err?.message?.search(`429:`) != -1,
    sdkError2: (err) => err?.message?.search(`Request was throttled.`) != -1
}

async function errorHandler<ApiFn extends PromiseFn>(
    predicate: ThrottlerPredicate,
    promiseFunction: ApiFn,
    thisArg: ThisParameterType<ApiFn>,
    ...args: Parameters<ApiFn>
): Promise<UnwrappedReturnType<ApiFn>> {
    let errCount = 0
    do {
        try {
            const promiseResult = await promiseFunction.call(thisArg, ...args)
            return promiseResult
        } catch (err: any) {
            //console.error(err)
            if (predicate(err)) {
                if (errCount < 20)
                    ++errCount;
                var ms = 1500 * errCount
            } else
                throw (err);
        }
    }
    while (true);
}

const fnc = (i:number) : Promise<boolean>  => Promise.resolve(true)

// Promise<boolean>
const res1 = errorHandler(errorPredicates.sdkError1, fnc, null, 4);

// Promise<any>
const res2 = errorHandler(errorPredicates.sdkError1, errorHandler, null, errorPredicates.sdkError2, fnc, null, 4);