我有一个数组，里面有这样的数据
arr1 = [
{mood: "good", name: "Jake"},
{mood: "good", name: "Jill"},
{mood: "good", name: "Jack"}
]
和另一个数组
arr2 = [
{number: 2, name: "Jake"},
{number: 1, name: "Jill"},
{number: 3, name: "Jack"}
]
我希望使用数组2中的数字对数组1进行排序.因此，基本上我需要使用过滤器将名称从arr1匹配到arr2，然后从结果数组中获取数字并进行排序.
我怎么才能把这件事做完？
arr1.sort((a: any, b: any) => arr1.filter((item: { name: string; }) => item.name == arr2[i].name));
我完全迷失了方向，以至于我可能没有问到一个合适的问题！
您可以简单地使用一个对象作为名称的顺序，并获取用于排序的值.
const
arr1 = [{ mood: "good", name: "Jake" }, { mood: "good", name: "Jill" }, { mood: "good", name: "Jack" }],
arr2 = [{ number: 2, name: "Jake" }, { number: 1, name: "Jill" }, { number: 3, name: "Jack" }],
order = Object.fromEntries(arr2.map(({ name, number }) => [name, number]));
arr1.sort((a, b) => order[a.name] - order[b.name]);
console.log(arr1);.as-console-wrapper { max-height: 100% !important; top: 0; }