Flutter iOS 键盘问题：. TextInputType.number 中缺少字符

发布于08月08日

在iOS设备上使用TextInputType.number时，我遇到了键盘上缺少"."(小数点)字符的问题.我已经正确地设置了输入格式化程序，只允许数字和".性格，但仍然是"."键盘上看不到字符.以下是我的代码片段:

Container(
                                              width: 65.w,
                                              height: 6.w,
                                              child: TextFormField(
                                                // The validator receives the text that the user has entered.
                                                controller:
                                                    _currentWeightController,
                                                textAlign: TextAlign.left,
                                                keyboardType: TextInputType.number,
                                                inputFormatters: [
                                                  FilteringTextInputFormatter
                                                      .allow(RegExp('[0-9.]')),
                                                ],
                                                style: TextStyle(
                                                    fontSize: 20,
                                                    color: Colors.black),

                                                // decoration: InputDecoration(
                                                //   hintText:
                                                //       '${num.parse(measurementRes[targetWeight] ?? "0").ceil().toString()}',
                                                // ),
                                              ),
                                            ),

该代码在Android上运行良好，既显示数字又显示".键盘上的字符.然而，在iOS设备上，".键盘上看不到字符.任何帮助都将不胜感激.

推荐答案

问题是在您的代码中，您使用的是:TextInputType.number

...针对无符号数字信息进行优化without a decimal point.

...
keyboardType: TextInputType.number,

相反，您应该使用:

keyboardType: const TextInputType.numberWithOptions(decimal: true),


Container(
      width: 65.w,
      height: 6.w,
      child: TextFormField(
        // The validator receives the text that the user has entered.
        controller: _currentWeightController,
        textAlign: TextAlign.left,
        keyboardType: const TextInputType.numberWithOptions(decimal: true),
        inputFormatters: [
          FilteringTextInputFormatter.allow(RegExp('[0-9.]')),
        ],
        style: TextStyle(fontSize: 20, color: Colors.black),

        // decoration: InputDecoration(
        //   hintText:
        //       '${num.parse(measurementRes[targetWeight] ?? "0").ceil().toString()}',
        // ),
      ),
    )