在 for 每个循环中使用 go routine 时，由 func 文字捕获的 go vet 范围变量

我不确定"func literal"是什么，所以这个错误让我有点困惑.我想我看到了这个问题——我从一个新的go routine 中引用了一个范围值变量，因此该值可能会随时发生变化，而不是我们所期望的.解决这个问题的最好方法是什么？

有问题的代码:

func (l *Loader) StartAsynchronous() []LoaderProcess {
    for _, currentProcess := range l.processes {
        cmd := exec.Command(currentProcess.Command, currentProcess.Arguments...)
        log.LogMessage("Asynchronously executing LoaderProcess: %+v", currentProcess)
        go func() {
            output, err := cmd.CombinedOutput()
            if err != nil {
                log.LogMessage("LoaderProcess exited with error status: %+v\n %v", currentProcess, err.Error())
            } else {
                log.LogMessage("LoaderProcess exited successfully: %+v", currentProcess)
                currentProcess.Log.LogMessage(string(output))
            }
            time.Sleep(time.Second * TIME_BETWEEN_SUCCESSIVE_ITERATIONS)
        }()
    }
    return l.processes
}

我建议的解决办法是:

func (l *Loader) StartAsynchronous() []LoaderProcess {
    for _, currentProcess := range l.processes {
        cmd := exec.Command(currentProcess.Command, currentProcess.Arguments...)
        log.LogMessage("Asynchronously executing LoaderProcess: %+v", currentProcess)
        localProcess := currentProcess
        go func() {
            output, err := cmd.CombinedOutput()
            if err != nil {
                log.LogMessage("LoaderProcess exited with error status: %+v\n %v", localProcess, err.Error())
            } else {
                log.LogMessage("LoaderProcess exited successfully: %+v", localProcess)
                localProcess.Log.LogMessage(string(output))
            }
            time.Sleep(time.Second * TIME_BETWEEN_SUCCESSIVE_ITERATIONS)
        }()
    }
    return l.processes
} 

但这真的能解决问题吗？我刚刚将引用从Range变量移动到另一个局部变量，该变量的值基于我所在的for each循环的迭代.