Flutter 有没有可能不在BlocBuilder中重新构建内容

我想推快餐店，如果国家是:

• PostSuccess -显示snackbar，通过Navigator.pop()转到上一个屏幕;
• 失败-显示Snackbar and not rebuild the listView.builder

              if (state is EduWorkPostSuccess) {
                showTopSnackBar(
                  Overlay.of(context),
                  CustomSnackBar.success(message: "Everything went alright"),
                );
                Navigator.pop(context);
              } else if (state is EduWorkFailed) {
                showTopSnackBar(
                  Overlay.of(context),
                  CustomSnackBar.error(
                      message: translation.translation[state.msg]),
                );
              }
            }, builder: (context, state) {
              if (state is EduWorkLoaded && state.isChanged) {
                return Padding(
                  padding: const EdgeInsets.all(15.0),
                  child: Center(
                    child: UserDataSectionDesription(
                      description:
                          "Remember to save your changes", //TODO added to translation file, w8ting...
                    ),
                  ),
                );
              } else {
                return SizedBox();
              }
            }

BlocBuilder<EduWorkBloc, EduWorkState>(
              builder: (context, state) {
                if (state is EduWorkLoading) {
                  return Center(
                      child: CircularProgressIndicator(
                    color: Theme.of(context).colorScheme.secondary,
                  ));
                } else if (state is EduWorkLoaded) {
                  return ListView.builder(
                    shrinkWrap: true,
                    itemCount: selectedMap.length,
                    itemBuilder: (context, index) {
                      return Padding(
                        padding: const EdgeInsets.all(8),
                        child: EducationWidget(
                          isSelected: state.eduWork.isSelectedEdu(
                              selectedMap.values.elementAt(index).toString()),
                          index: index,
                          code: selectedMap.values.elementAt(index).toString(),
                          name: selectedMap.keys.elementAt(index).toString(),
                          onPressed: () {
                            final codeName =
                                selectedMap.values.elementAt(index).toString();
                            //if that level of education is selected unselect it
                            if (state.eduWork.education.contains(codeName)) {
                              state.eduWork.education.remove(codeName);

                              BlocProvider.of<EduWorkBloc>(context)
                                  .add(ChangeEdu(state.eduWork));

                              //If unselected add it
                            } else {
                              state.eduWork.education.add(codeName);

                              BlocProvider.of<EduWorkBloc>(context)
                                  .add(ChangeEdu(state.eduWork));
                            }
                          },
                        ),
                      );
                    },
                  );
                }
                return Text('Error');
              },
            ),

此时此刻，.Success正在正常运作.当状态为FAIL时，Snackbar会正常显示，但会返回文本(‘Error)’.我怎么才能解决这个问题？