Flutter如何从深入嵌套的小部件中打开抽屉

您可以创建一个全局键变量并将其传递到此处.

例如

final GlobalKey<ScaffoldState> globalScaffoldKey = GlobalKey();

class YourMainScreen extends StatefulWidget {
  const YourMainScreen({Key? key}) : super(key: key);

  @override
  State<YourMainScreen> createState() => _YourMainScreenState();
}

class _YourMainScreenState extends State<YourMainScreen> {
  @override
  Widget build(BuildContext context) {
    return WillPopScope(
      onWillPop: _systemBackButtonPressed,
      child: Scaffold(
        key: globalScaffoldKey, // Global Key
        drawer: const MenuDrawer(),
        bottomNavigationBar: BottomNavigationBar(...),
          ],
          currentIndex: _selectedIndex,
          onTap: _onItemTapped,
        ),
        body: SafeArea(
          top: false,
          child: IndexedStack(
            index: _selectedIndex,
            children: const <Widget>[
              MenuNavigator(),
              CabinetNavigator(),
              SearchNavigator(),
              ContactsNavigator(),
              CartNavigator()
            ],
          ),
        ),
      ),
    );
  }
}

然后，您可以通过调用从任何位置打开抽屉

globalScaffoldKey.currentState!.openDrawer()