Django Forms：将参数传递给表单

发布于02月02日

如何将参数传递给窗体？

someView()..
    form = StylesForm(data_dict) # I also want to pass in site_id here.

class StylesForm(forms.Form):
    # I want access to site_id here

推荐答案

您应该定义表单的_init__方法，如下所示:

class StylesForm(forms.Form):
    def __init__(self,*args,**kwargs):
        self.site_id = kwargs.pop('site_id')
        super(StylesForm,self).__init__(*args,**kwargs)

当然你不能进入self .创建对象之前的站点id，因此该行:

     height = forms.CharField(widget=forms.TextInput(attrs={'size':site_id}))

这说不通.在创建表单之后，您必须将属性添加到小部件.试着这样做:

class StylesForm(forms.Form):
    def __init__(self,*args,**kwargs):
        self.site_id = kwargs.pop('site_id')
        super(StylesForm,self).__init__(*args,**kwargs)
        self.fields['height'].widget = forms.TextInput(attrs={'size':site_id})

    height = forms.CharField()

(未测试)