Dart Flutter 网页打开网址并获取数据

发布于07月18日

如何打开url并获取数据.

这是代码:

void main() {
  runApp(MaterialApp(
    home: new Scaffold(
      body: new Center(
        child: new ElevatedButton(
          onPressed: () {
            //_launchInBrowser(Uri(scheme: 'https', host: "dart.dev"));
            var data = html.window.open("https://dart.dev", "dart dev");
            print(data.location);
          },
          child: new Text('Show Flutter homepage'),
        ),
      ),
    ),
  ));
}

Future<void> _launchInBrowser(Uri url) async {
  if (!await launchUrl(
    url,
    mode: LaunchMode.externalApplication,
  )) {
    throw 'Could not launch $url';
  }
}

推荐答案

我找到了这个解决方案或解决方法.

<script>
    var data = window.open("http://dart.dev");
    //alert(window.location.href);
    localStorage.setItem("url", window.location.href);
    console.log(localStorage.getItem("url"));
</script>

我需要的网址，但它可以存储任何数据从页面.

使用本地存储:

import 'dart:html' as html;

class LocalStorage {
  final html.Storage _localStorage = html.window.localStorage;

  Future save(String url) async {
    _localStorage['url'] = url;
  }

  Future<String?> getUrl() async => _localStorage['url'];

  Future invalidate() async {
    _localStorage.remove('url');
  }
}

我try 使用shared_首选项，但不起作用.

ElevatedButton(
          onPressed: () async {
            var rep = LocalStorage();
            await _launchInBrowser(Uri(path: "open_url.html"));
            print(await rep.getUrl());
          },
          child: Text('Show Flutter homepage'),
        ),    
    Future<void> _launchInBrowser(Uri url) async {
      if (!await launchUrl(
        url,
        mode: LaunchMode.externalApplication,
      )) {
        throw 'Could not launch $url';
      }
    }