我试图找到一种方法来调用泛型类型上的方法.但是找不到.
用Swift 我可以这样写:
protocol SomeGeneric {
static func createOne() -> Self
func doSomething()
}
class Foo: SomeGeneric {
required init() {
}
static func createOne() -> Self {
return self.init()
}
func doSomething() {
print("Hey this is fooooo")
}
}
class Bar: SomeGeneric {
required init() {
}
static func createOne() -> Self {
return self.init()
}
func doSomething() {
print("Hey this is barrrrrrr")
}
}
func create<T: SomeGeneric>() -> T {
return T.createOne()
}
let foo: Foo = create()
let bar: Bar = create()
foo.doSomething() //prints Hey this is fooooo
bar.doSomething() //prints Hey this is barrrrrrr
在DART中,我try 过:
abstract class SomeGeneric {
SomeGeneric createOne();
void doSomething();
}
class Foo extends SomeGeneric {
@override
SomeGeneric createOne() {
return Foo();
}
@override
void doSomething() {
print("Hey this is fooooo");
}
}
class Bar extends SomeGeneric {
@override
SomeGeneric createOne() {
return Bar();
}
@override
void doSomething() {
print("Hey this is barrrrr");
}
}
T create<T extends SomeGeneric>() {
return T.createOne();//error: The method 'createOne' isn't defined for the class 'Type'.
}
代码给出错误The method 'createOne' isn't defined for the class 'Type'
如何解决这个问题?如果这是可能的,它将节省大量的时间和大量的代码行.