C++ 在创建动态泛型数组时，通过realloc对故障进行分段

我试图实现一个动态泛型array.然而，当我测试我的代码时，我得到的结果是"分段错误".我知道这个错误是由函数ArrayListReSize中的realloc引起的，但是为什么呢？

以下是我实现的几个方法:

typedef struct ArrayList {
  void** arr;
  size_t allocated, len;
} ArrayList;

int ArrayListInit(ArrayList *list) {
  list = (ArrayList *)malloc(sizeof(ArrayList));
  if (list == NULL) {
    fprintf(stderr, FAILED_ALLOCATION_MSG);
    return -1;
  }
  list->allocated = 0;
  list->len = 0;
  list->arr = (void **)NULL;
  return 0;
}

int ArrayListAppend(ArrayList *list, void *item) {
  if (item == NULL) {
    fprintf(stderr, INVALID_ARG_MSG);
    return -1;
  }
  if (ArrayListResize(list, list->len + 1) == -1) {
    return -1;
  }
  list->arr[list->len] = item;
  return 0;
}

int ArrayListResize(ArrayList *list, size_t len) {
  void **arr;
  size_t allocated = list->allocated, new_allocated;
  if (allocated >= len && len >= (allocated >> 1)) {
    assert(list->arr != NULL || len == 0);
    list->len = len;
    return 0;
  }
  if (len == 0)
    new_allocated = 0;
  else
    new_allocated = len + (len >> 3) + (len < 9 ? 3 : 6);
  arr = (void**)realloc(list->arr, sizeof(void *) * new_allocated); // Here I get the segmentation fault
  if (arr == NULL) {
    fprintf(stderr, FAILED_REALLOCATION_MSG);
    return -1;
  }
  list->arr = arr;
  list->allocated = new_allocated;
  list->len = len;
  return 0;
}

这是测试代码:

int* GenerateIntPointer(int n) {
  int* ptr_int = (int*)malloc(sizeof(int));
  *ptr_int = n;
  return ptr_int;
}

int main() {
  ArrayList list;
  ArrayListInit(&list);
  for (size_t i = 0; i < 10; i++) {
    ArrayListAppend(&list, (void*)GenerateIntPointer((int)i));
  }
  ArrayListDelete(&list, free);
  return 0;
}