def convert_number(input_number): def decimal_to_binary(n): return bin(n).replace("0b", "") def binary_to_decimal(b): return int(b, 2) def decimal_to_bcd(n): return ''.join(bin(int(digit)).replace("0b", "").rjust(4, '0') for digit in str(n)) def bcd_to_decimal(bcd): decimal = 0 for i in range(0, len(bcd), 4): decimal = decimal * 10 + binary_to_decimal(bcd[i:i+4]) return decimal prefix, value = input_number.split(":", 1) if prefix.lower() == "dec": decimal = int(value) binary = decimal_to_binary(decimal) bcd = decimal_to_bcd(decimal) elif prefix.lower() == "bin": binary = value decimal = binary_to_decimal(binary) bcd = decimal_to_bcd(decimal) elif prefix.lower() == "bcd": bcd = value decimal = bcd_to_decimal(bcd) binary = decimal_to_binary(decimal) else: return "Unknown format." return f"Decimal: {decimal}, Binary: {binary}, BCD: {bcd}" # Examples print(convert_number("dec:45")) # Decimal input print(convert_number("bin:101101")) # Binary input print(convert_number("bcd:01000101")) # BCD input#Python Interactive Shell >>> int('1001011', 2) 75double binaryToDecimal(char binary[DIM]) { char binary2[DIM] = "", floa[DIM] = ""; double decimal = 0, negDec = 0, flo = 0; int count = 0, j = 0, i = 0, f = 0, g = 0, h = 0, count1 = 0, d = 0, k = 0; while (binary[d] != '\0'&&binary[d] != '.') { d++; } d--; if (binary[0] == '-') { while (binary[k] != '\0') { binary[k] = binary[k + 1]; k++; } k = 0; while (binary[k] == '0') { d--; k++; } negDec = pot(2.000, d*1.000, 1); } while (binary[i] != '\0'&&binary[i] != '.') { i++; } i--; count = i; h = i; while (binary[h] != '\0') { floa[g] = binary[h + 2]; g++; h++; } g--; count1 = g; while (i >= 0) { binary2[j] = binary[i]; i--; j++; } binary2[j] = '\0'; while (i <= count) { if (binary2[i] == '1') { decimal = decimal + pot(2.000, i, 1); } i++; } h = -1; g = 0; while (g <= count1) { if (floa[g] == '1') { flo = flo + pot(2.000, h, 1); } g++; h--; } decimal = decimal + flo; if (negDec > 0) { decimal = (decimal - negDec); if (flo > 0) { double f = fl(decimal); f = 1 - f; decimal = returnDeciPart(decimal) - f; } } return decimal; }#include <stdio.h> int main() { int num, binary_val, decimal_val = 0, base = 1, rem; printf("Insert a binary num (1s and 0s) \n"); scanf("%d", &num); binary_val = num; while (num > 0) { rem = num % 10; decimal_val = decimal_val + rem * base; num = num / 10 ; //these are the correct lines base = base * 2; //these are the correct lines } printf("%d \n", binary_val); printf("%d \n", decimal_val); return 0; }//* How to convert a decimal number into a binary number #include <bits/stdc++.h> using namespace std; class NumberConversion { int n = 0, count = 0, ans = 0; public: void decimalToBinary(int n) { this->n = n; while (this->n != 0) { int rem = this->n % 2; this->n /= 2; ans += rem * pow(10, count); count++; } } void display() { cout << ans << endl; } }; int main() { int number = 0; cin >> number; NumberConversion num1; num1.decimalToBinary(number); num1.display(); return 0; }