print max activity by greedy technique in java
// The following implementation assumes that the activities // are already sorted according to their finish time import java.util.*; import java.lang.*; import java.io.*; class ActivitySelection { // Prints a maximum set of activities that can be done by a single // person, one at a time. // n --> Total number of activities // s[] --> An array that contains start time of all activities // f[] --> An array that contains finish time of all activities public static void printMaxActivities(int s[], int f[], int n) { int i, j; System.out.print("Following activities are selected : n"); // The first activity always gets selected i = 0; System.out.print(i+" "); // Consider rest of the activities for (j = 1; j < n; j++) { // If this activity has start time greater than or // equal to the finish time of previously selected // activity, then select it if (s[j] >= f[i]) { System.out.print(j+" "); i = j; } } } // driver program to test above function public static void main(String[] args) { int s[] = {1, 3, 0, 5, 8, 5}; int f[] = {2, 4, 6, 7, 9, 9}; int n = s.length; printMaxActivities(s, f, n); } }
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