Typescript重复功能实现

发布于09月26日

我在同一个Typescript类中定义了以下两个函数签名，即:.，

public emit<T1>(event: string, arg1: T1): void {}

和

public emit<T1,T2>(event: string, arg1: T1, arg2: T2): void {}

然而，当传输typescript时，我得到了以下错误

error TS2393: Duplicate function implementation.

I thought you could overload functions in typescript providing the number of parameters in the function signature were different. Given that the above signatures have 2 和 3 parameters respectively, why am I getting this transpilation error?

推荐答案

我假设您的代码如下所示:

public emit<T1>(event: string, arg1: T1): void {}
public emit<T1,T2>(event: string, arg1: T1, arg2: T2): void {}
public emit(event: string, ...args: any[]): void {
    // actual implementation here
}

问题是前两行之后有{}个.这实际上定义了一个函数的empty implementation，例如:

function empty() {}

您只需要为函数定义type，而不是implementation.因此，用分号替换空块:

public emit<T1>(event: string, arg1: T1): void;
public emit<T1,T2>(event: string, arg1: T1, arg2: T2): void;
public emit(event: string, ...args: any[]): void {
    // actual implementation here
}