Typescript可以导出功能吗

发布于03月27日

是否可以从typescript模块导出简单函数？

module SayHi {
    export function() {
    console.log("Hi");
  }
}
new SayHi();

This workitem似乎意味着你不能，但并不是直截了当地说出来.不可能吗？

推荐答案

在那个例子中，很难说你想要什么.exports =是关于从external个模块导出，但您链接的代码示例是internal个模块.

经验法则:如果你写module foo { ... }，那你就是在写一个内部模块；如果你在一个文件的顶层写export something something，你就在写一个外部模块.实际上，在顶层写export module foo是有点罕见的(从那时起，你会将名称双重嵌套)，而在具有顶层导出的文件中写module foo则更为罕见(因为foo在外部是不可见的).

以下几点是有意义的(每个场景由一条横向规则描述):

// An internal module named SayHi with an exported function 'foo'
module SayHi {
    export function foo() {
       console.log("Hi");
    }

    export class bar { }
}

// N.B. this line could be in another file that has a
// <reference> tag to the file that has 'module SayHi' in it
SayHi.foo();
var b = new SayHi.bar();

file1.ts

// This *file* is an external module because it has a top-level 'export'
export function foo() {
    console.log('hi');
}

export class bar { }

file2.ts

// This file is also an external module because it has an 'import' declaration
import f1 = module('file1');
f1.foo();
var b = new f1.bar();

file1.ts

// This will only work in 0.9.0+. This file is an external
// module because it has a top-level 'export'
function f() { }
function g() { }
export = { alpha: f, beta: g };

file2.ts

// This file is also an external module because it has an 'import' declaration
import f1 = require('file1');
f1.alpha(); // invokes f
f1.beta(); // invokes g