Swift ：如何在一组字符之后得到所有东西

发布于12月04日

给定以下字符串:

var snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"

如何提取"Phone:"之后的所有内容

所以在这种情况下我想要

phone = 123.456.7891

我试过这个:

    if let range = snippet.rangeOfString("Phone:") {

        let phone = snippet.substringToIndex(range.startIndex)
        print(phone) // prints 1111 West Main Street Beverly Hills, CA 90210
    }

但这会打印之前的所有内容，之后我需要所有内容.

推荐答案

在Swift 4中，使用upperBound和下标运算符和开放范围:

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"

if let range = snippet.range(of: "Phone: ") {
    let phone = snippet[range.upperBound...]
    print(phone) // prints "123.456.7891"
}

或者考虑修剪空白:

if let range = snippet.range(of: "Phone:") {
    let phone = snippet[range.upperBound...].trimmingCharacters(in: .whitespaces)
    print(phone) // prints "123.456.7891"
}

顺便说一句，如果您试图同时获取这两个函数，正则表达式可以做到这一点:

let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
let regex = try! NSRegularExpression(pattern: #"^(.*?)\s*Phone:\s*(.*)$"#, options: .caseInsensitive)
if let match = regex.firstMatch(in: snippet, range: NSRange(snippet.startIndex..., in: snippet)) {
    let address = snippet[Range(match.range(at: 1), in: snippet)!]
    let phone = snippet[Range(match.range(at: 2), in: snippet)!]
}

有关以前版本的Swift，请参见previous revision of this answer.