empno | ename | job | mgr | hiredate | sal | deptno |
---|---|---|---|---|---|---|
7839 | KING | PRESIDENT | 2031-11-17 | 5000.00 | 10 | |
7934 | MILLER | CLERK | 7782 | 2032-01-23 | 1300.00 | 10 |
7782 | CLARK | MANAGER | 7839 | 2031-06-09 | 2450.00 | 10 |
7369 | SMITH | CLERK | 7902 | 2030-12-17 | 800.00 | 20 |
7876 | ADAMS | CLERK | 7788 | 2037-05-23 | 1100.00 | 20 |
7566 | JONES | MANAGER | 7839 | 2031-04-02 | 2975.00 | 20 |
7902 | FORD | ANALYST | 7566 | 2031-12-03 | 3000.00 | 20 |
7788 | SCOTT | ANALYST | 7566 | 2037-04-19 | 2900.00 | 20 |
7521 | WARD | SALESMAN | 7698 | 2031-02-22 | 1250.00 | 30 |
7844 | TURNER | SALESMAN | 7698 | 2031-09-08 | 1500.00 | 30 |
7900 | JAMES | CLERK | 7698 | 2031-12-03 | 950.00 | 30 |
7499 | ALLEN | SALESMAN | 7698 | 2031-02-20 | 1600.00 | 30 |
7698 | BLAKE | MANAGER | 7839 | 2031-05-01 | 2850.00 | 30 |
7654 | MARTIN | SALESMAN | 7698 | 2031-09-28 | 1250.00 | 30 |
我有一张表格,里面有员工的数据.我想问的是,如何找到一个拥有比最低级别的sal经理更大的sal经理,而他/她拥有相同的部门.而且这份工作不是总裁或经理.
例如,在德普诺20号球场,最低级别的赛尔经理应该是2975的琼斯.有比琼斯大的萨尔,和琼斯有同样的德普诺的人是福特,所以我想把这个打印出来.
select ename,sal from emp
where sal >= all(select min(sal) from emp where job = 'MANAGER' group by deptno)
and job not like 'PRESIDENT'
and job not like 'MANAGER'
group by deptno, ename,sal;
实际上,这种sql工作得很好,可以打印出来,但当我再次查看时,我注意到,当我使用all时,它只是与where子句中取出的所有数据进行比较,而不是按deptno编号分组进行比较.