如何获得:
id Name Value
1 A 4
1 B 8
2 C 9
到
id Column
1 A:4, B:8
2 C:9
如何获得:
id Name Value
1 A 4
1 B 8
2 C 9
到
id Column
1 A:4, B:8
2 C:9
No CURSOR, WHILE loop, or User-Defined Function needed
只需要对XML和PATH进行创新.
[注意:此解决方案仅适用于SQL 2005及更高版本.原始问题未指定正在使用的版本.]
CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)
SELECT
[ID],
STUFF((
SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX))
FROM #YourTable
WHERE (ID = Results.ID)
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID
DROP TABLE #YourTable