正如标题所述,为什么要编译以下代码?
use std::ops::Deref;
struct Foo {}
fn main() {
let b = Box::new(Foo{});
let pb = *b; //works
// let pb = *b.deref(); // error[E0507]: cannot move out of a shared reference
}
对于具有非复制目标的自定义类型,情况并非如此.
use std::ops::Deref;
struct Foo<T> {
p: T,
}
impl<T> Deref for Foo<T> {
type Target = T;
fn deref(&self) -> &<Self as Deref>::Target {
&self.p
}
}
fn main() {
let f = Foo { p: vec![1u8] };
let pf = *f; // error[E0507]: cannot move out of a shared reference
let pf = *f.deref(); // error[E0507]: cannot move out of a shared reference
}
*Box
不是*Box.deref()
吗?