有没有更直接易读的方法来实现以下目标:
fn main() {
let a = [1, 2, 3];
let b = [4, 5, 6];
let c = [7, 8, 9];
let iter = a.iter()
.zip(b.iter())
.zip(c.iter())
.map(|((x, y), z)| (x, y, z));
}
也就是说,我如何从n个iterables生成n个元组来构建迭代器?