Rust 使用枚举对 struct 进行分组

在Rust中，应该如何对相关 struct 进行分组，以便函数签名可以在引用方法体中的具体类型时接受多个不同的类型？

为了简单起见，设计了以下示例:

enum Command {
    Increment {quantity: u32},
    Decrement {quantity: u32},
}

fn process_command(command: Command) {
    match command {
        Command::Increment => increase(command),
        Command::Decrement => decrease(command),
    };
}

fn increase(increment: Command::Increment) {
    println!("Increasing by: {}.", increment.quantity);
}

fn decrease(decrement: Command::Decrement) {
    println!("Decreasing by: {}.", decrement.quantity);
}

fn main() {
    let input = "Add";
    let quantity = 4;

    let command: Command = match input {
        "Add" => Command::Increment { quantity: quantity },
        "Subtract" => Command::Decrement { quantity: quantity },
        _ => unreachable!(),
    };

    process_command(command);
}

编译会导致以下两个错误:

src/main.rs:13:24: 13:42 error: found value name used as a type: DefVariant(DefId { krate: 0, node: 4 }, DefId { krate: 0, node: 5 }, true) [E0248]
src/main.rs:13 fn increase(increment: Command::Increment) {
                                      ^~~~~~~~~~~~~~~~~~
src/main.rs:17:24: 17:42 error: found value name used as a type: DefVariant(DefId { krate: 0, node: 4 }, DefId { krate: 0, node: 8 }, true) [E0248]
src/main.rs:17 fn decrease(decrement: Command::Decrement) {
                                      ^~~~~~~~~~~~~~~~~~
error: aborting due to 2 previous errors

如果我单独声明 struct ，并将 struct 包装在元组 struct 中(正确的术语？)枚举中的每一个都会得到预期的结果，但由于到处都是冗长和相似的类型名，我怀疑我误解了某些东西:

struct Increment {
    quantity: u32,
}

struct Decrement {
    quantity: u32,
}

enum Command {
    Increment(Increment),
    Decrement(Decrement),
}

fn process_command(command: Command) {
    match command {
        Command::Increment(increment) => increase(increment),
        Command::Decrement(decrement) => decrease(decrement),
    };
}

fn increase(increment: Increment) {
    println!("Increasing by: {}.", increment.quantity);
}

fn decrease(decrement: Decrement) {
    println!("Decreasing by: {}.", decrement.quantity);
}

fn main() {
    let input = "Add";
    let quantity = 4;

    let command: Command = match input {
        "Add" => Command::Increment(Increment { quantity: quantity }),
        "Subtract" => Command::Decrement(Decrement { quantity: quantity }),
        _ => unreachable!(),
    };

    process_command(command);
}

运行输出:

Increasing by: 4.

是否在枚举类型(术语？)中包装 struct 同名真的是最好的解决方案吗？Command::Increment(Increment { quantity: 7 })