things = "one thing, two things, three things, four things"
有了这个输入，我如何用逗号分割一个字符串，然后将其周围的空格修剪到位？导致:
things = ["one thing", "two things", "three things", "four things"]
目前我有:
things = things.to_s.tr("\n\t", "").strip.split(/,/)
这完成了我希望它完成的大部分工作，除了在逗号上拆分时删除前导/尾随空格.实现这一目标的最佳方式是什么？我想把它作为这个表达式的一部分，而不是把上面的结果赋给一个单独的数组，然后对它进行迭代.
s = "one thing, two things, three things, four things"
s.split(",").map(&:strip)
# => ["one thing", "two things", "three things", "four things"]
在我的Ubuntu 13.04操作系统中，使用Ruby 2.0.0p0
require 'benchmark'
s = "one thing, two things, three things, four things"
result = ""
Benchmark.bmbm do |b|
b.report("strip/split: ") { 1_000_000.times {result = s.split(",").map(&:strip)} }
b.report("regex: ") { 1_000_000.times {result = s.split(/\s*,\s*/)} }
end
Rehearsal -------------------------------------------------
strip/split: 6.260000 0.000000 6.260000 ( 6.276583)
regex: 7.310000 0.000000 7.310000 ( 7.320001)
--------------------------------------- total: 13.570000sec
user system total real
strip/split: 6.350000 0.000000 6.350000 ( 6.363127)
regex: 7.290000 0.000000 7.290000 ( 7.302163)