我在db中有一个datetime列,当我向用户显示它时,我想将其转换为一个简单的日期.
我该怎么做?
def shown_date # to_date does not exist, but is what I am looking for self.date || self.exif_date_time_original.to_date end
我在db中有一个datetime列,当我向用户显示它时,我想将其转换为一个简单的日期.
我该怎么做?
def shown_date # to_date does not exist, but is what I am looking for self.date || self.exif_date_time_original.to_date end
DateTime#to_date
确实存在于ActiveSupport中:
$ irb
>> DateTime.new.to_date
NoMethodError: undefined method 'to_date' for #<DateTime: -1/2,0,2299161>
from (irb):1
>> require 'active_support/core_ext'
=> true
>> DateTime.new.to_date
=> Mon, 01 Jan -4712