Reactjs Firebase删除UserWithEmail AndPassword仅创建匿名用户

我正在用Firebase的用户名和密码方法为我的网站编写帐户创建功能.当前的实现不工作，除非我启用匿名用户创建模式，然后只创建匿名用户，这不是我想要的.为什么这段代码没有创建经过身份验证的用户，因为这是Firebase要求代码的实现方式？

import { getAuth, createUserWithEmailAndPassword } from "firebase/auth";
import { initializeApp } from "firebase/app";

const SignUp = () => {

    const firebaseConfig = {
        apiKey: "{apiKey}",
        authDomain: "{domain}",
        projectId: "{projectID}",
        storageBucket: "{bucket}",
        messagingSenderId: "{id}",
        appId: "{id}",
        measurementId: "{id}"
    };
      
    const app = initializeApp(firebaseConfig);

    const userSignUp = ({ email, password }) => {
        const auth = getAuth(app);
        createUserWithEmailAndPassword(auth, email, password)
        .then((userCredential) => {
            const user = userCredential.user;
            console.log(user);
        })
        .catch((error) => {
            const errorCode = error.code;
            const errorMessage = error.message;
            console.log(errorMessage);
        });
    };

    function handleSignUp(e) {
        e.preventDefault();
        const form = e.target;
        const formData = new FormData(form);
        const formJson = Object.fromEntries(formData.entries());
        console.log(formJson.email + " " + formJson.password)
        userSignUp(formJson.email, formJson.password);
    }

    return(
        <>
            <h1>Sign Up</h1>
            <form method="post" onSubmit={handleSignUp}>
                <label>
                    Email: <input type="email" name="email"/>
                </label>
                <label>
                    Password: <input type="password" name="password"/>
                </label>
                <button type="submit">Submit</button>
            </form>
        </>
    );
}

export default SignUp

这样做的结果就是这个错误:

Jsx:20 POST https://identitytoolkit.googleapis.com/v1/accounts:signUp?key=AIzaSyA4EnTbw40XnyYjHRHYjvWAxJ42STDF3cA 400(Bad Request)

这个控制台消息:

Firebase:错误(auth/admin—restricted—operation).