ReactJS：唯一项目的数量总和

我有以下对象/数组:

[
    {
        "id": null,
        "value": "Apples",
        "label": "Apples",
        "Quantity": 1,
        "Weight": "0.075",
        "inputQuantity": "2",
        "Category": "BREAKFAST",
        "ItemCopy": 2,
        "PM": "123"
    },
    {
        "Quantity": 1,
        "value": "Apples",
        "Weight": "0.075",
        "id": null,
        "label": "Apples",
        "inputQuantity": "3",
        "Category": "BREAKFAST",
        "ItemCopy": 2,
        "PM": "123"
    },
    {
        "value": "Asparagus",
        "id": "TnwiO97ZHCsz4vl9A9OR",
        "label": "Asparagus",
        "Weight": "0.185",
        "Quantity": 1,
        "inputQuantity": "3",
        "Category": "BREAKFAST",
        "ItemCopy": 1,
        "PM": "123"
    }
]

然后，我使用以下代码将它们简化为唯一值:

  function getUniqueDataCount(objArr, propName) {
    const mi = [...objArr]
    var data = [];
    objArr.forEach(function (d, index) {
      if (d[propName]) {
        data.push(d[propName]);
      }
    });
    var uniqueList = [...new Set(data)];
    var dataSet = {};
    for (var i = 0; i < data.length; i++) {
      dataSet[uniqueList[i]] = data.filter(x => x == uniqueList[i]).length;
      mi[i].ItemCopy = data.filter(x => x == data[i]).length
    }
    return mi;
  }

 useMemo(() => {
    mydata = getUniqueDataCount(daataa, 'label');
  }, [daataa])

  useMemo(() => {
    newCheck = Object.values(mydata?.reduce((acc, cur) => Object.assign(acc, { [cur?.label]: cur }), {}))
  }, [mydata])

然后，新的Check对象/数组变为:

[
    {
        "Quantity": 1,
        "value": "Apples",
        "Weight": "0.075",
        "id": null,
        "label": "Apples",
        "inputQuantity": "2",
        "Category": "BREAKFAST",
        "ItemCopy": 2
    },
    {
        "value": "Asparagus",
        "id": "TnwiO97ZHCsz4vl9A9OR",
        "label": "Asparagus",
        "Weight": "0.185",
        "Quantity": 1,
        "inputQuantity": "2",
        "Category": "BREAKFAST",
        "ItemCopy": 1
    }
]

这或多或少是我想要的，但是在这个newCheck对象/数组中，它没有正确地计算inputQuantity-对于苹果，它应该是5，对于芦笋，它应该是3.

我如何修改它，以便 for each 唯一的配料获得每次出现的inputQuantity？