Reactjs 在 React 中使用forwardRef时无法声明自定义属性

在Reaction中使用ForwardRef时，我不能声明自定义属性；这可以用<MyInput ref={ref}></MyInput>，但我不能像这样向它添加自定义属性:

<MyInput someval={someval} ref={ref}></MyInput>个

错误是

"某些值不能分配给内部属性(&A；RefAttributes)"

//this is the parent component
export const Recognizer: React.FunctionComponent = () => {

  const ref = useRef(null);

  function handleClick() {
    ref.current.focus();
  }

  const [someval, setSomeVal] = useState(1);


return ( <div>
      <MyInput  someval={someval} ref={ref}></MyInput>
      <Button onClick={handleClick}>test</Button>)
};

// child component 

const MyInput = forwardRef(function MyInput(prop, ref) {
  const inputRef = useRef(null);

  useImperativeHandle(
    ref,
    () => {
      return {
        focus() {
          console.log("calling focus");
          inputRef.current.focus();
        },
        scrollIntoView() {
          console.log("calling scroll");
          inputRef.current.scrollIntoView();
        },
      };
    },
    []
  );

  return <div ref={inputRef} />;
});

export default MyInput;