Reactjs Reactredux 组件不会在存储状态更改时重新渲染

今天我要学习react和redux，但我不知道如何在状态更改后强制组件重新加载.

这是我的代码:

const store = createStore(loginReducer);
export function logout() { return {type: 'USER_LOGIN'} }
export function logout() { return {type: 'USER_LOGOUT'} }
export function loginReducer(state={isLogged:false}, action) {
  switch(action.type) {
    case 'USER_LOGIN':
      return {isLogged:true};
    case 'USER_LOGOUT':
      return {isLogged:false};
    default:


         return state;
      }
    }

    class App extends Component {

      lout(){
        console.log(store.getState()); //IT SHOW INITIAL STATE
        store.dispatch(login());
        console.log(store.getState()); //IT SHOWS THAT STATE DID CHANGE
      }

      ////THIS IS THE PROBLEM, 
    render(){
    console.log('rendering')
    if(store.getState().isLogged){
      return (<MainComponent store={store} />);
    }else{
      return (
        <View style={style.container}>
          <Text onPress={this.lout}>
          THE FOLLOWING NEVER UPDATE :( !!{store.getState().isLogged?'True':'False'}</Text>
          </View>
        );
    }    
}

触发更新的唯一方法是使用

store.subscribe(()=>{this.setState({reload:false})});

在构造函数内部，所以我手动触发组件的更新状态以强制重新加载.

但是我如何链接存储和组件状态呢？