我正试图通过基于搜索栏文本的平面列表进行搜索.我遇到的问题是,当用户输入错误时...如果他们想输入"burger",但错误地输入了"burget",那么它将不会返回应有的结果.当用户删除"t"时,它应该再次使用与"burge"部分匹配的最后一个文本重新呈现平面列表.
注意:使用react native elements搜索栏,只需e或event即可调用文本.
到目前为止,我所拥有的一切.js文件:
searchText = (e) => {
let text = e.toLowerCase();
let trucks = this.state.data;
// search by food truck name
let filteredName = trucks.filter((truck) => {
return truck.name.toLowerCase().match(text);
});
// if no match and text is empty
if(!text || text === '') {
console.log('change state');
this.setState({
data: initial
});
}
// if no name matches to text output
else if(!Array.isArray(filteredName) && !filteredName.length) {
console.log("not name");
this.setState({
data: [],
});
}
// if name matches then display
else if(Array.isArray(filteredName)) {
console.log('Name');
this.setState({
data: filteredName,
});
}
};
<View style={styles.container}>
<SearchBar
round
lightTheme
containerStyle={styles.search}
ref="search"
textInputRef="searchText"
onChangeText={this.searchText.bind(this)}
placeholder='Search by Truck Name...'
/>
<TruckList getTruck={(truck) => this.setTruck(truck)} truckScreen={this.truckScreen} data={this.state.data}/>
</View>
然后是卡车司机.JS:
export default class TruckList extends Component {
// rendering truck screen
renderTruckScreen = (item) => {
this.props.truckScreen();
this.props.getTruck(item);
}
render() {
return(
<List style={styles.list}>
<FlatList
data={this.props.data}
renderItem={({ item }) => (
<ListItem
roundAvatar
avatar={{uri: item.pic1}}
avatarStyle={styles.avatar}
title={item.name}
titleStyle={styles.title}
subtitle={
<View style={styles.subtitleView}>
<Text style={styles.subtitleFood}>{item.food}</Text>
<View style={styles.subtitleInfo}>
<Icon
name="favorite"
size={20}
color={"#f44336"}
style={styles.subtitleFavorite}
/>
<Text style={styles.subtitleFavoriteText}>{item.favorited} favorited</Text>
</View>
</View>
}
onPress={() => this.renderTruckScreen(item)}
/>
)}
keyExtractor={(item) => item.uid}
ListFooterComponent={this.footer}
/>
</List>
)
}
}
我试过其他几种方法,但都没有用.此外,我在React Native上看到的唯一解决方案是ListView,它会随着时间的推移而贬值.所以我try 用新的平面列表组件来实现这一点.
谢谢你的帮助!