使用带有OR条件的grepl过滤字符串

目前我的df如下所示:

df <- data.frame(
  player = c('Player To Have 1 Or More Shots On Target', 'Player To Have 1 Or More Shots On Target', 
             'Player To Have 2 Or More Shots On Target', 'Player To Have 3 Or More Shots On Target',
             'Player To Have 1 Or More Shots On Target in 1st Half'))

输出:

                                                player
1             Player To Have 1 Or More Shots On Target
2             Player To Have 1 Or More Shots On Target
3             Player To Have 2 Or More Shots On Target
4             Player To Have 3 Or More Shots On Target
5 Player To Have 1 Or More Shots On Target in 1st Half

我想使用grepl(或另一个合适的替代方案)来仅捕获目标上的1、2、3、4等镜头(忽略其他任何内容，如第5行，其中也包含"in first Half").

在上面的示例中，我希望捕获前4行(原始数据有更多行).我try 了以下有效的方法:

df2 <- dplyr::filter(df, grepl("Player To Have 1 Or More Shots On Target", player))

如何才能省略上述字符，使其包含多个数字"1"？例如，我想拍摄1、2、3、4等镜头？

我try 了一些类似的方法:

number_of_shots <- c("1","2")
df2 <- dplyr::filter(df, grepl("Player To Have", number_of_shots, "Or More Shots On Target", player))

但我得到以下错误:

Error in `dplyr::filter()`:
ℹ In argument: `grepl(...)`.
Caused by error:
! `..1` must be of size 5 or 1, not size 2.