library(data.table)
dat1 <- data.table(id1 = c(1, 1, 2),
pattern = c("apple", "applejack", "bananas, sweet"))
dat2 <- data.table(id2 = c(1174, 1231),
description = c("apple is sweet", "apple is a computer"),
memo = c("bananas, sweet yes", "bananas, sweetyes"))
> dat1
id1 pattern
1: 1 apple
2: 1 applejack
3: 2 bananas, sweet
> dat2
id2 description memo
1: 1174 apple is sweet bananas, sweet yes
2: 1231 apple is a computer bananas, sweetyes
我有两张data.table
的,dat1
和dat2
.我想根据dat2
中的description
和memo
列搜索dat2
中的每个pattern
,并存储相应的id2
.
最终的输出表应该如下所示:
id1 pattern description_match memo_match
1: 1 apple 1174,1231 <NA>
2: 1 applejack <NA> <NA>
3: 2 bananas, sweet <NA> 1174
我想使用的正则表达式是\\b[pattern]\\b
.以下是我的try :
dat1[, description_match := dat2[grepl(paste0("\\b", dat1$pattern, "\\b"), dat2$description), .(id2 = paste(id2, collapse = ","))]]
dat1[, memo_match := dat2[grepl(paste0("\\b", dat1$pattern, "\\b"), dat2$memo), .(id2 = paste(id2, collapse = ","))]]
然而,两者都给了我一个错误,即grepl
只能使用前pattern
.