Python 如何删除重复的文字翻拍

from rich import print

target_word = 'flass'
solved = False 
word = input('Enter a word: ')
if len(word) == 5 :
    n = 0
    while n < 6 and not solved:
        hw = [""] * 5
        nongreen = []
        green = []
        dublicate = set()
        if word != target_word:
            for i in range(0,5):
                if word[i] == target_word[i]:
                    hw[i] = "[green]" + target_word[i]
                    green.append(word[i])
                else:    
                    nongreen.append(word[i])
            for i in range(0,5):
                if not hw[i]:
                    if word[i] in target_word and word[i] not in green:
                        hw[i] ="[yellow]" + word[i]
                    else:
                        hw[i] ="[white]" + word[i]    
            print("".join(hw))
            word = input('Enter a word: ')
        else:
            solved = True
        n += 1  
        if solved:
            print("[green]" + target_word)
            print(f'You got it in {n} tries')
        else:
            print(f'Try {n+1}')
    if not solved:
        print("you've exhausted all tries.")
else:
    print("Please enter5 characters.")

in code you check only char is not in green. 但是如果你在target_word中添加char，使用这个条件判断char是否存在.