Python 如何使用Selify和XPath定位按钮

第一个问题-你试图找到多个元素，这将产生list，但这些元素没有方法点击.

第二个问题-您的 Select ，没有a有这样的class你试图寻找.

因此，请将您的 Select 更改为:

driver.find_element(By.XPATH, '//li[@class=" pagination-next"]/a')

为了以防万一，请查看expliced waits和try / except的概念，并可能使用while loop来迭代页面:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
from bs4 import BeautifulSoup
import time
from selenium.webdriver.common.by import By

# Create a new instance of the Chrome driver
driver = webdriver.Chrome()

# Go to the webpage
driver.get('https://is.muni.cz/predmet/?volby=obory:4382@fakulta:1433@obdobi:podzim%202023,jaro%202024@jazyky:eng')

links = []

while True:
    
    website = driver.page_source
    soup = BeautifulSoup(website, 'html.parser')

    links.extend(['https://is.muni.cz' + link['href'] for link in soup.find_all('a', class_='course_link')])
    
    try:
        WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, '//li[@class=" pagination-next"]/a'))).click()
    except TimeoutException:
        break

print(links)

driver.quit()