Python 传递了形状数组(2，4)和(2，1)的pyfunc中的S执行了8(2*4)次，而不是2次

我有一个函数x，如下所示，它接受两个NumPy数组作为输入，并且我想通过一些计算得到一个布尔值.

import numpy as np

def x(a,b):
    print(a)
    print(b)
    # Some computation...
    return boolean_value

wrappedFunc = np.frompyfunc(x,nin=2,nout=1)

arg_a = np.arange(8).reshape(2,4)
# arg_b is a numpy array having shape (2,1)
arg_b = np.array((np.array([[0, 1, 0],
                            [0, 0, 0],
                            [1, 0, 0],
                            [1, 1, 0]]),
                  np.array([[0., 1., 0.],
                            [0., 0., 0.],
                            [1., 0., 0.],
                            [1., 1., 0.],
                            [0.5, 0.5, 0.]])), dtype=object).reshape(2, 1)

执行上面的代码将产生以下输出.

# Output of a is:
0
1
2
3
4
5
6
7
# output of b is:
[[0 1 0]
 [0 0 0]
 [1 0 0]
 [1 1 0]]

[[0 1 0]
 [0 0 0]
 [1 0 0]
 [1 1 0]]

[[0 1 0]
 [0 0 0]
 [1 0 0]
 [1 1 0]]

[[0 1 0]
 [0 0 0]
 [1 0 0]
 [1 1 0]]

[[0.  1.  0. ]
 [0.  0.  0. ]
 [1.  0.  0. ]
 [1.  1.  0. ]
 [0.5 0.5 0. ]]

[[0.  1.  0. ]
 [0.  0.  0. ]
 [1.  0.  0. ]
 [1.  1.  0. ]
 [0.5 0.5 0. ]]

[[0.  1.  0. ]
 [0.  0.  0. ]
 [1.  0.  0. ]
 [1.  1.  0. ]
 [0.5 0.5 0. ]]

[[0.  1.  0. ]
 [0.  0.  0. ]
 [1.  0.  0. ]
 [1.  1.  0. ]
 [0.5 0.5 0. ]]

正如您可以看到的，变量a和b分别打印了8次，这不是预期的行为，因为我预计会分别看到a和b的打印语句的输出两次.print(a)和print(b)语句的预期输出如下所示:

On first call:
a needs to be:[0,1,2,3]
b needs to be:[[0 1 0]
              [0 0 0]
              [1 0 0]
              [1 1 0]]
On second call:
a needs to be:[4,5,6,7]
b needs to be:[[0.  1.  0. ]
              [0.  0.  0. ]
              [1.  0.  0. ]
              [1.  1.  0. ]
              [0.5 0.5 0. ]]

我到底做错了什么？