Python 从列表dict中减go 另一个列表中的重复序列

请考虑以下代码:

def scrape_data(url, wanted_list):
    scraper = AutoScraper()
    scraper.build(url, wanted_list)
    result = scraper.get_result_similar(url, unique=False)
    return result

name_result = scrape_data(url, ["names"])

previous_name = []
with open("name.csv", "r", encoding="utf-8") as name_file:
    reader = csv.reader(name_file)
    for row in reader:
        try:
            i = 0
            while True:
                previous_name.append(row[i])
                i += 1
        except(IndexError):
            pass


#Insert here the code to operate the subtraction

with open("new_name.csv", "w", newline="", encoding="utf-8") as file:
    writer = csv.writer(file)
    writer.writerow(result)

其中previous_name是列表，是name_result的副本，是列表|dict，minus a variable number of elements at the beginning，例如:

name_result = ["James", "Robert", "John", "Michael", "James", "Barbara", "Jessica"]
previous_name = [                   "John", "Michael", "James", "Barbara", "Jessica"]

我想要一个减法，它将这些第一个元素输出为变量result，即name_result的非重复"头"，即在本例中:["James", "Robert"]

这不是基于元素的减法:previous_name中存在"James"，但所需的输出不是["Robert"].

问题是，到目前为止，我所try 的只相当于元素减法(输出["Robert"]):

• How to subtract strings in python个

set1 = set(list1)
set2 = set(list2)
set1 - set2

• How do I subtract one list from another?个

[x for x in list1 if x not in list2]