Python 遍历pandas列中的嵌套列表，并根据嵌套列表中的值创建字典

我有一个数据框，比如:

id        some_binary_col        some_amount_col        nested_lists
123       0                      100                    ['email_rule','phone_rule','score_rule']
456       1                      500                    ['address_rule','zip_rule']
121       1                      300                    ['zip_rule','phone_rule']
122       0                      100                    ['score_rule','phone_rule','new_rule']
133       1                      200                    ['email_rule','address_rule','zip_rule']

可重现性:

ids = [123,456,121,122,133]
some_binary_col = [0,1,1,0,1]
some_amount_col = [100,500,300,100,200]
nested_lists = [
    ['email_rule','phone_rule','score_rule']
    ,['address_rule','zip_rule']
    ,['zip_rule','phone_rule']
    ,['score_rule','phone_rule','new_rule']
    ,['email_rule','address_rule','zip_rule']
]

df = pd.DataFrame()
df['id'] = ids
df['some_binary_col'] = some_binary_col
df['some_amount_col'] = some_amount_col
df['nested_lists'] = nested_lists

我正在制作一本新的词典，它能计算nested_loop列中每个规则的some_binary_col if=1，如下所示:

rule_binary_col_dict = {
    'email_rule': 1
    ,'phone_rule': 1
    ,'score_rule': 0
    ,'address_rule': 2
    ,'zip_rule': 3
    ,'new_rules': 0
}

这nested_list个可以有无限的唯一列表/元素.

我不太擅长的是遍历嵌套列表中的每个元素…… 比如:

for i in df['nested_lists']:
    for j in i:
        **some condition**

我不知道如何访问嵌套列表中的每个元素.