输入:
x = ( (1,"A", 10),(1,"B", 10),(1,"B", 10),(1,"C", 10),(1,"C", 10),(1,"B", 10),(1,"A", 10),(1,"A", 10),(1,"C", 10),(1,"B", 10))
预期输出:
{'A': [(1, 'A', 10), (7, 'A', 70), (8, 'A', 80)], 'B': [(2, 'B', 20), (3, 'B', 30), (6, 'B', 60), (10, 'B', 100)], 'C': [(4, 'C', 40), (5, 'C', 50), (9, 'C', 90)]}
基本上是根据元组中的一个元素对元组进行分组
我试过了,但感觉不像是古典式的
def consolidate(values):
res = {}
for a in values:
if a[1] in res:
p = res[a[1]]
p.append(a)
res[a[1]] = p
else:
res[a[1]] = [a]
return res