Python 范围变量未检测给定范围内的浮点数值

range仅生成整数.例如，range(2,6)将生成(2，3，4，5).

您的问题可以通过以下方式解决:

address="xyz"
size="6.33"
if address == 0 and float(size)>=1 and  float(size)<5:
    print("1")
elif address == 0 and float(size)>=5 and  float(size)<8:          
    print("2")
elif address != 0 and float(size)>=5 and  float(size)<8:         
    print("3")
elif address == 0 and float(size)>=8 and  float(size)<10:        
    print("4")
elif address != 0 and float(size)>=10 and  float(size)<19:         
    print("5")
elif address == 0 and float(size)>=10 and  float(size)<19:          
    print("6")
elif address != 0 and float(size)>=20 and  float(size)<100:         
    print("7")
elif address == 0 and float(size)>=20 and  float(size)<100:   
    print("8")
else:           
    print("9")

或者更有效地，使用嵌套条件，

address="xyz"
size="6.33"
if address == 0:
    if float(size)>=1 and  float(size)<5:
        print("1")
    elif float(size)>=5 and float(size)<8:          
        print("2")
    elif float(size)>=8 and float(size)<10:          
        print("4")
    elif float(size)>=10 and float(size)<19:          
        print("6")
    elif float(size)>=20 and float(size)<100:          
        print("8")
    else:
        print("9")
else:
    if float(size)>=5 and float(size)<8:          
        print("3")
    elif float(size)>=10 and float(size)<19:          
        print("5")
    elif float(size)>=20 and float(size)<100:          
        print("7")
    else:
        print("9")