Python 如何在没有递归的情况下在该函数中返回到函数的开头

class PlayerAttributes:
        inventory = []
        def __init__(self, name, inventory):
            self.name = name
            self.inventory = inventory # LIST
    class Item:
        def __init__(self, item_name, damage):
            self.item_name = item_name
            self.damage = damage

class Weapons(Item):
    weapon_1 = Item("Me Sword", 100)


Player_1 = PlayerAttributes("Bob", [])

def get_name():
    Player_1.name = input("Enter name here: ").capitalize()
    commands()

def stats():
    print("Name = " + str(Player_1.name), "\n",
          "Inventory: ")
    for x in Player_1.inventory:
        print(str(x.item_name))

def commands():
    prompt = None
    prompt_choices = {"stats", "quit", "give"}
    while prompt not in prompt_choices:
        prompt = input("Enter Command: ").lower()
    if prompt == "stats":
        stats()
        commands()
    elif prompt == "quit":
        quit()
    elif prompt == "give":
        Player_1.inventory.append(Weapons.weapon_1)
        commands()

get_name()

PROBLEM

我现在通过在if语句中调用"commands()"返回"prompt"的while循环，但被告知这是一个递归，没有必要，而且它有一个增加调用堆栈的副作用...

QUESTION

我应该怎么做？？

Extra

它将如何增加调用堆栈？