将 Matlab 转换为 python 代码：IndexError： index 1 is out of bounds for axis 0 with size 0

发布于06月27日

将Matlab代码转换为python.索引器错误:索引-1超出大小为0的轴0的界限

for i = 1:N
            for j=1:N
                s = zeros(L2,L2);
                sX = zeros(L2,L2);
                sSS= Y((i-1)*L2+1:i*L2,(j-1)*L2+1:j*L2);
                BI{i,j} = sSS;

Python

for i in range(N):
        for j in range(N):
            s = zeros(N, N);
            sX = zeros(N,N);
            sSS =Y[arange(dot((i - 1),L2) + 1,dot(i,L2)),arange(dot((j - 1),L2) + 1,dot(j,L2))]
            BI [i,j] = sSS

索引器错误:索引-1超出大小为0的轴0的界限.根据BI[i，j]=sSS的线.

推荐答案

MATLAB索引(i-1)*L2+1:i*L2,(j-1)*L2+1:j*L2简单地转换为Python的索引i*L2:(i+1)*L2, j*L2:(j+1)*L2.您应该在循环外部初始化BI，在循环内部初始化s、sX.此外，Y未在循环外部定义.

注意，您不应该像这样从numpy导入所有内容，它应该是import numpy as np，并且可以在任何需要的地方使用np.func(..).BI在MATLAB中定义为更接近cell array的列表.

from numpy import *    # not recommended to import everything

N = L2 = 5
Y = random.rand(100,100)
BI = []
for i in range(N):
    BI.append([])
    for j in range(N):
        # s = zeros((L2,L2))  # does nothing
        # sX = zeros((L2,L2)) # does nothing
        sSS = Y[i*L2:(i+1)*L2, j*L2:(j+1)*L2]
        BI[i].append(sSS)