Python3.x Python：字典和列表：在列表字典中搜索子列表的有效方法

我有一段在列表字典中搜索字符串列表的Python代码.它目前可以工作；但是我的代码遍历字典中的每个条目，然后try 找到与子列表匹配的列表.如果词典很大，我的代码就不会有效率.有没有更好/更有效的方法来做到这一点？

我的python代码如下:

from collections import defaultdict
import numpy as np
from bisect import bisect_left

def matchingStringsByKeys(dictionary, searchString):
        return [val for key, val in dictionary.items() if searchString in key]
    
def getsublist(firstArr, secondArr):
    
            # Maps elements of firstArr[]
            # to their respective indices
        mp = {}
    
        print('len(firstArr): %s' % str(len(firstArr)))
            # Traverse the array firstArr[]
    
        for i in range(len(firstArr)):
                mp[firstArr[i]] = i + 1
    
            # Stores the indices of common elements
            # between firstArr[] and secondArr[]
        tempArr = []
    
            # Traverse the array secondArr[]
        for i in range(len(secondArr)):                
            returned_keys = matchingStringsByKeys(mp, secondArr[i])
            if (len(returned_keys) > 0):
                print('Match found for: %s' % secondArr[i])
                for k in returned_keys:
                    tempArr.append(k)
    
        tail = []
        tempArrLen = len(tempArr)
        if ( tempArrLen > 0):
                    # Stores lIS from tempArr[]
            tail.append(tempArr[0])
            for i in range(1, len(tempArr)):
                if (tempArr[i] > tail[-1]):
                    tail.append(tempArr[i])
                elif (tempArr[i] < tail[0]):                                
                    tail.insert(0, tempArr[i])
                else :
                    it = bisect_left(tail, tempArr[i])
                    tail.insert(it, tempArr[i])
        else:
            print('Did not find a match')                
    
        return tail
    
    
#keyword_list = ['men', 'boy']
keyword_list = ['men', 'boy', 'dog']
#db_data={'male':['man', 'men'], 'child':['boy','lad', 'girl'], 'animal':['cat','dog']}

db_data={'male':['1:man', '2:men'], 'child':['3:boy','4:lad', '5:girl'], 'animal':['6:cat','7:dog, puppy']}


output = defaultdict(list)
for key, value in db_data.items():
    print('\nchecking in: %s\n ' % (value))
    a = np.array(value)
    b = a.ravel()
    result = getsublist(b, keyword_list)
    print('Result: %s' % (result))
    for x in result:
        output[key].append(b[x-1])
    
print(output)