Postgresql 合并两个字典并创建一个包含更新凭据的字典列表

给出了词典

    dict1:
      a_username: a1
      a_password: apass1
      b_username: b1
      b_password: bpass1
      c_username: c1
      c_password: cpass1
      
    dict2:
      a_username: a2
      a_password: apass2
      b_username: b1
      b_password: bpass1
      c_username: c2
      c_password: cpass1

问:100

A:模板如下

    list1: |
      {% filter from_yaml %}
      {% for i in dict1.keys()|batch(2) %}
      - {username: {{ dict1[i.0] }}, password: {{ dict1[i.1] }}}
      {% if dict1[i.0] != dict2[i.0] or dict1[i.1] != dict2[i.1] %}
      - {username: {{ dict2[i.0] }}, password: {{ dict2[i.1] }}}
      {% endif %}
      {% endfor %}
      {% endfilter %}

赠送

    list1:
      - {password: apass1, username: a1}
      - {password: apass2, username: a2}
      - {password: bpass1, username: b1}
      - {password: cpass1, username: c1}
      - {password: cpass1, username: c2}

下一个选项是获取唯一的用户名/密码对并创建词典

    dict3: "{{ dict((dict1.values()|list + dict2.values()|list)|
                    batch(2)|unique) }}"

赠送

    dict3:
      a1: apass1
      a2: apass2
      b1: bpass1
      c1: cpass1
      c2: cpass1

将词典转换为列表，您会得到相同的结果

    list1: "{{ dict3|
               dict2items(key_name='username', value_name='password')|
               sort(attribute='username') }}"