Postgresql 返回 array_agg() 中的第一个元素

我正在写一个查询，以获取所有球队的所有球员.我没有在应用程序中循环，而是决定使用array_agg()在一个查询中获得所有球队的球员.我已经把这个问题写了如下:

SELECT team_id, array_agg(team_name) AS teamname,
       array_agg(player_id||'##'||player_name) AS playerdetails
FROM team
INNER JOIN players ON team_id = player_team
GROUP BY team_id

这个查询给我的结果如下，在结果集中，teamname是重复的(精确到玩家数量)

team_id             team_name                                                                   playerdetails
1       {Australia,Australia,Australia,Australia}                       {"5##Glenn Donald McGrath","6##Shane Warne","2##Steve Waugh","1##Adam Gilchrist"}
2       {India,India,India,India}                                       {"8##Kapil Dev","11##Saurav Ganguly","3##Rahul Dravid","9##Sachin Tendulkar"}
3       {"South Africa","South Africa","South Africa","South Africa"}   {"12##Gary Kristen","4##Shaun Pollock","7##Jacques Kallis","10##Alan Donald"}

有没有办法像这样返回结果

team_id             team_name                                                                   playerdetails
1                   Australia                       {"5##Glenn Donald McGrath","6##Shane Warne","2##Steve Waugh","1##Adam Gilchrist"}

我已经使用子查询实现了它，但是我想知道是否可以在没有子查询的情况下编写它

SELECT team_id, teamname[1], playerdetails
FROM (
  SELECT team_id, array_agg(team_name) AS teamname,
         array_agg(player_id||'##'||player_name) AS playerdetails
  FROM team
  INNER JOIN players ON team_id = player_team
  GROUP BY team_id) AS tempresult  

sqfiddle人在这里.我使用的是Postgresql 8.4

[EDIT]

SELECT team_id, array_agg(team_name) AS teamname,
       array_agg(player_id||'##'||player_name) AS playerdetails,
       team_status -- could be replaced by something like array_agg(team_status)[0] or customfunction(team_status)
FROM team
INNER JOIN players ON team_id = player_team
GROUP BY team_id