我让gwt应用程序在后端连接到postgres DB,一个java类"Decision"在DB中映射表"Decisions",当我试图将一个判断持久化到DB中时,它抛出了以下错误:
Caused by: org.hibernate.exception.SQLGrammarException: could not get next sequence value
...
Caused by: org.postgresql.util.PSQLException: ERROR: relation "hibernate_sequence" does not exist
我的判断课是这样的
@Entity
@Table(name = "JUDGEMENTS")
public class Judgement implements Serializable, Cloneable {
private static final long serialVersionUID = -7049957706738879274L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "JUD_ID")
private Long _judId;
...
我的判断是:
Column | Type | Modifiers
-------------+-----------------------------+---------------------------------------------------------
jud_id | bigint | not null default nextval('judgements_id_seq'::regclass)
rating | character varying(255) |
last_update | timestamp without time zone |
user_id | character varying(255) |
id | integer |
Indexes:
"judgements_pkey" PRIMARY KEY, btree (jud_id)
Foreign-key constraints:
"judgements_id_fkey" FOREIGN KEY (id) REFERENCES recommendations(id)
"judgements_user_id_fkey" FOREIGN KEY (user_id) REFERENCES users(user_id)
我在DB中有一个序列名'judictions_id_seq'
有人能告诉我怎么了吗???谢谢