在php中计算两个没有假期的日期之间的小时差

下面是一个例子:

date_default_timezone_set('Asia/Jakarta');
$awal  = date_create("2023-08-18 00:00:00");
$akhir = date_create("2023-08-21 00:00:00");

// Array of holidays
$holidays = array("2023-08-19"); // Example holiday. Add more dates as needed.

$interval = DateInterval::createFromDateString('1 day');
$periods = new DatePeriod($awal, $interval, $akhir);

$holidayHours = 0;
foreach ($periods as $period) {
    if (in_array($period->format('Y-m-d'), $holidays)) {
        $holidayHours += 24; // Exclude 24 hours for each holiday
    }
}

$diff  = date_diff($awal, $akhir);
$hariNya = $diff->d;
$jamNya = $diff->h;
$menitNya = $diff->i;

if($jamNya < 10){
    $jamNya2 = "0".$jamNya;
} else {
    $jamNya2 = $jamNya;
}

if($menitNya < 10){
    $menitNya2 = "0".$menitNya;
} else {
    $menitNya2 = $menitNya;
}

if($hariNya < 1){
    $durasi = $jamNya2.":".$menitNya2;
} elseif($hariNya >= 1) {
    $gg = $hariNya * 24;
    $ff = $gg+$jamNya2 - $holidayHours; // Subtract holiday hours from total
    $durasi = $ff.":".$menitNya2;
}

echo $durasi;

我在本例中添加了这$holidays = array("2023-08-19");.您必须在此数组中添加假期天数.